![]() Continue normally because you know its setĪnd like has been said, you can shorthand the ternary and just use: $target_val = $values ?: null īut you will get a notice thrown on array value not set so I always just use isset and assign a value in the ternary to avoid silencing messages for no reason. I know that the value is not set and if I want to check if it is set: if(!!$target_val)Īnd it may be a bit verbose but you can do it all in one swoop like this: if(!($target_val = isset($values) ? $values : null)) ![]() in this example if I do: if(!$target_val) If the PHP isset() function are passed with the multiple variables then isset() will TRUE only if all the variables are set. The return type of the isset() function of PHP programming language is Boolean. You can set a default value and if your using a false evaluating value as the default its easy to see if the variable was set. The isset() function works from the PHP version 4.0. I settled on this because it appeared to be the most versatile. The isset () function will return true when all variables passed into the function are declared, and their values are not null. $target_val = isset($values) ? $values : null Sorry to open this up again, but I spent a good 20 min testing out cases because this conversation did so many loops through multiple techniques but didn't appear to settle. ![]() This function was removed in PHP 8, if you are using it in your applications, the code. Best way is always the ternary operators. Returns the current key/value pair of an array and advances its cursor. The second check is needed because some values evaluated with isset() will result false despite the index does exist.
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